| 如何使用asp上传HTML5 单input多文件 |
lH41p0 http://blog.numino.net/
If you have a form which submits multiple values of the same form variable you can separate them as follows.
4kE95a http://blog.numino.net/
For i = 1 to Request.form("myforminput").Count
6x11xh http://blog.numino.net/
If Request.form("myforminput")(i) <> "" then
OuR62R http://blog.numino.net/
Response.write Request.form("myforminput")(i) & "<br />"
fpU66M http://blog.numino.net/
End if
tVf1yg http://blog.numino.net/
Next
ZD4kkK http://blog.numino.net/
It might be worth trying the same approach - ie:
lLc80p http://blog.numino.net/
For i = 1 to (objUpload.Form("thefile").value).Count
rpU6W1 http://blog.numino.net/
If (objUpload.Form("thefile").value)(i) <> "" then
TSl0Tx http://blog.numino.net/
Response.write (objUpload.Form("thefile").value)(i) & "<br />"
QuBo3c http://blog.numino.net/
End if
T55hFY http://blog.numino.net/
Next
HAy0DZ http://blog.numino.net/
Because there's a third party component involved it may complicate things so I can't guarantee this will work. Check the component's documentation if it is available, particularly with respect to counting the number of files uploaded.
nv2Uqj http://blog.numino.net/
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