| 如何使用asp上传HTML5 单input多文件 |
z7n4Ok http://blog.numino.net/
If you have a form which submits multiple values of the same form variable you can separate them as follows.
1AgQb4 http://blog.numino.net/
For i = 1 to Request.form("myforminput").Count
D9wEHw http://blog.numino.net/
If Request.form("myforminput")(i) <> "" then
2faa1F http://blog.numino.net/
Response.write Request.form("myforminput")(i) & "<br />"
leUc3s http://blog.numino.net/
End if
COub3x http://blog.numino.net/
Next
bCMFXy http://blog.numino.net/
It might be worth trying the same approach - ie:
41z8aD http://blog.numino.net/
For i = 1 to (objUpload.Form("thefile").value).Count
V6ruu4 http://blog.numino.net/
If (objUpload.Form("thefile").value)(i) <> "" then
l7DGI7 http://blog.numino.net/
Response.write (objUpload.Form("thefile").value)(i) & "<br />"
6yz6Ft http://blog.numino.net/
End if
SR2vl5 http://blog.numino.net/
Next
LQsaMR http://blog.numino.net/
Because there's a third party component involved it may complicate things so I can't guarantee this will work. Check the component's documentation if it is available, particularly with respect to counting the number of files uploaded.
xb91UK http://blog.numino.net/
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