| 如何使用asp上传HTML5 单input多文件 |
N0W0Vo http://blog.numino.net/
If you have a form which submits multiple values of the same form variable you can separate them as follows.
CeeC8q http://blog.numino.net/
For i = 1 to Request.form("myforminput").Count
kb6lRP http://blog.numino.net/
If Request.form("myforminput")(i) <> "" then
o7N7ZQ http://blog.numino.net/
Response.write Request.form("myforminput")(i) & "<br />"
U58Bnj http://blog.numino.net/
End if
2XzaVc http://blog.numino.net/
Next
sX4EtJ http://blog.numino.net/
It might be worth trying the same approach - ie:
r016n0 http://blog.numino.net/
For i = 1 to (objUpload.Form("thefile").value).Count
XyytIx http://blog.numino.net/
If (objUpload.Form("thefile").value)(i) <> "" then
oN0U8m http://blog.numino.net/
Response.write (objUpload.Form("thefile").value)(i) & "<br />"
WS7dGu http://blog.numino.net/
End if
LBD8zS http://blog.numino.net/
Next
RHGFFU http://blog.numino.net/
Because there's a third party component involved it may complicate things so I can't guarantee this will work. Check the component's documentation if it is available, particularly with respect to counting the number of files uploaded.
gtoe6m http://blog.numino.net/
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