| 如何使用asp上传HTML5 单input多文件 |
IxmV4q http://blog.numino.net/
If you have a form which submits multiple values of the same form variable you can separate them as follows.
O2gCPB http://blog.numino.net/
For i = 1 to Request.form("myforminput").Count
IP4n2E http://blog.numino.net/
If Request.form("myforminput")(i) <> "" then
t7SBui http://blog.numino.net/
Response.write Request.form("myforminput")(i) & "<br />"
1E5JqL http://blog.numino.net/
End if
j9x7sp http://blog.numino.net/
Next
PO3oqj http://blog.numino.net/
It might be worth trying the same approach - ie:
Bnl8VH http://blog.numino.net/
For i = 1 to (objUpload.Form("thefile").value).Count
u01tro http://blog.numino.net/
If (objUpload.Form("thefile").value)(i) <> "" then
c7LR8x http://blog.numino.net/
Response.write (objUpload.Form("thefile").value)(i) & "<br />"
8kter7 http://blog.numino.net/
End if
835bkr http://blog.numino.net/
Next
LIaWQD http://blog.numino.net/
Because there's a third party component involved it may complicate things so I can't guarantee this will work. Check the component's documentation if it is available, particularly with respect to counting the number of files uploaded.
jFyy3b http://blog.numino.net/
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