| 如何使用asp上传HTML5 单input多文件 |
wx12OH http://blog.numino.net/
If you have a form which submits multiple values of the same form variable you can separate them as follows.
LKq49d http://blog.numino.net/
For i = 1 to Request.form("myforminput").Count
3q80lY http://blog.numino.net/
If Request.form("myforminput")(i) <> "" then
v8cTmP http://blog.numino.net/
Response.write Request.form("myforminput")(i) & "<br />"
iFeP67 http://blog.numino.net/
End if
ch7O4n http://blog.numino.net/
Next
TzzDYG http://blog.numino.net/
It might be worth trying the same approach - ie:
0S4nvd http://blog.numino.net/
For i = 1 to (objUpload.Form("thefile").value).Count
CK43Pp http://blog.numino.net/
If (objUpload.Form("thefile").value)(i) <> "" then
xE0UVO http://blog.numino.net/
Response.write (objUpload.Form("thefile").value)(i) & "<br />"
xrqAFy http://blog.numino.net/
End if
LYVlyp http://blog.numino.net/
Next
2KiYfp http://blog.numino.net/
Because there's a third party component involved it may complicate things so I can't guarantee this will work. Check the component's documentation if it is available, particularly with respect to counting the number of files uploaded.
IICBZF http://blog.numino.net/
|
|