| 如何使用asp上传HTML5 单input多文件 |
fjq6UM http://blog.numino.net/
If you have a form which submits multiple values of the same form variable you can separate them as follows.
fc2M2v http://blog.numino.net/
For i = 1 to Request.form("myforminput").Count
3De396 http://blog.numino.net/
If Request.form("myforminput")(i) <> "" then
IDQwZW http://blog.numino.net/
Response.write Request.form("myforminput")(i) & "<br />"
4hky3J http://blog.numino.net/
End if
478Rv5 http://blog.numino.net/
Next
k1d2FG http://blog.numino.net/
It might be worth trying the same approach - ie:
VSxc27 http://blog.numino.net/
For i = 1 to (objUpload.Form("thefile").value).Count
kJfQ1J http://blog.numino.net/
If (objUpload.Form("thefile").value)(i) <> "" then
ko468i http://blog.numino.net/
Response.write (objUpload.Form("thefile").value)(i) & "<br />"
hMp2rk http://blog.numino.net/
End if
JBvhlB http://blog.numino.net/
Next
m72z5q http://blog.numino.net/
Because there's a third party component involved it may complicate things so I can't guarantee this will work. Check the component's documentation if it is available, particularly with respect to counting the number of files uploaded.
58KA3a http://blog.numino.net/
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